Using Cramer's Rule | PuzzledQuant

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Easy

Discrete Maths

Consider the linear system $A\mathbf{x} = \mathbf{b}$ with

$A = \begin{bmatrix} t & 2 \\ -2 & t+3 \end{bmatrix}, \qquad \mathbf{b} = \begin{bmatrix} 1 \\ -4 \end{bmatrix}.$

For which value of $t$ does the system have a solution with $x_1 = 0$ ?

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